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صراحةً المنتدى متعطل والسبب هو هذا الخطأ .. من الفجر أحاول فيه ما ادري من وين اجيبة
سويت اصلاح للجداول , مانفع افرغت جدول سيزون مانفع هذا الخطأ بين يديكم ويارب القى حل من يديكم
كود PHP:
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html>
<head>
<title>ali Database Error</title>
<meta **********="Content-Type" content="text/html; charset=ISO-8859-1" />
<style type="text/css">
<!--
body { background-color: white; color: black; }
#container { width: 400px; }
#message { width: 400px; color: black; background-color: #FFFFCC; }
#bodytitle { font: 13pt/15pt verdana, arial, sans-serif; height: 35px; vertical-align: top; }
.bodytext { font: 8pt/11pt verdana, arial, sans-serif; }
a:link { font: 8pt/11pt verdana, arial, sans-serif; color: red; }
a:visited { font: 8pt/11pt verdana, arial, sans-serif; color: #4e4e4e; }
-->
</style>
</head>
<body>
<table cellpadding="3" cellspacing="5" id="container">
<tr>
<td><img src="./image.php?type=dberror" alt="Database Error" width="48" height="48" /></td>
<td id="bodytitle" width="100%">Database error</td>
</tr>
<tr>
<td class="bodytext" colspan="2">The ali database has encountered a problem.</td>
</tr>
<tr>
<td colspan="2"><hr /></td>
</tr>
<tr>
<td class="bodytext" colspan="2">
Please try the following:
<ul>
<li>Load the page again by clicking the <a href="#" onclick="window.location = window.location;">*******</a> button in your web browser.</li>
<li>Open the <a href="/">www.xxx.com</a> home page, then try to open another page.</li>
<li>Click the <a href="java******:history.back(1)">Back</a> button to try another link.</li>
</ul>
</td>
</tr>
<tr>
<td class="bodytext" colspan="2">The www.xxxx.com forum technical staff have been notified of the error, though you may <a href="mailto:dbmaster@example.com">contact them</a> if the problem persists.</td>
</tr>
<tr>
<td class="bodytext" colspan="2"> <br />We apologise for any inconvenience.</td>
</tr>
</table>
<!--
Database error in vBulletin 3.6.2:
Invalid SQL:
SELECT
user.username, (user.options & 512) AS invisible, user.usergroupid,
session.userid, session.inforum, session.lastactivity,
IF(displaygroupid=0, user.usergroupid, displaygroupid) AS displaygroupid, infractiongroupid
FROM session AS session
LEFT JOIN user AS user ON(user.userid = session.userid)
WHERE session.lastactivity > 1161367743
ORDER BY username ASC;
MySQL Error : Unknown column 'infractiongroupid' in 'field list'
Error Number : 1054
Date : Friday, October 20th 2006 @ 09:24:03 PM
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